Use generational stack for idle connections
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committed by
Jack Christensen
parent
3009dbab62
commit
d970a39050
@@ -0,0 +1,85 @@
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package genstack
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// GenStack implements a generational stack.
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//
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// GenStack works as common stack except for the fact that all elements in the
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// older generation are guaranteed to be popped before any element in the newer
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// generation. New elements are always pushed to the current (newest)
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// generation.
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//
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// We could also say that GenStack behaves as a stack in case of a single
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// generation, but it behaves as a queue of individual generation stacks.
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type GenStack[T any] struct {
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// We can represent arbitrary number of generations using 2 stacks. The
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// new stack stores all new pushes and the old stack serves all reads.
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// Old stack can represent multiple generations. If old == new, then all
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// elements pushed in previous (not current) generations have already
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// been popped.
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old *stack[T]
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new *stack[T]
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}
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// NewGenStack creates a new empty GenStack.
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func NewGenStack[T any]() *GenStack[T] {
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s := &stack[T]{}
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return &GenStack[T]{
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old: s,
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new: s,
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}
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}
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func (s *GenStack[T]) Pop() (T, bool) {
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// Pushes always append to the new stack, so if the old once becomes
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// empty, it will remail empty forever.
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if s.old.len() == 0 && s.old != s.new {
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s.old = s.new
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}
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if s.old.len() == 0 {
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var zero T
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return zero, false
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}
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return s.old.pop(), true
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}
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// Push pushes a new element at the top of the stack.
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func (s *GenStack[T]) Push(v T) { s.new.push(v) }
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// NextGen starts a new stack generation.
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func (s *GenStack[T]) NextGen() {
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if s.old == s.new {
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s.new = &stack[T]{}
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return
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}
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// We need to pop from the old stack to the top of the new stack. Let's
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// have an example:
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//
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// Old: <bottom> 4 3 2 1
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// New: <bottom> 8 7 6 5
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// PopOrder: 1 2 3 4 5 6 7 8
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//
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//
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// To preserve pop order, we have to take all elements from the old
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// stack and push them to the top of new stack:
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//
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// New: 8 7 6 5 4 3 2 1
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//
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s.new.push(s.old.takeAll()...)
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// We have the old stack allocated and empty, so why not to reuse it as
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// new new stack.
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s.old, s.new = s.new, s.old
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}
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// Len returns number of elements in the stack.
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func (s *GenStack[T]) Len() int {
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l := s.old.len()
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if s.old != s.new {
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l += s.new.len()
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}
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return l
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}
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@@ -0,0 +1,90 @@
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package genstack
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import (
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"testing"
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"github.com/stretchr/testify/require"
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)
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func requirePopEmpty[T any](t testing.TB, s *GenStack[T]) {
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v, ok := s.Pop()
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require.False(t, ok)
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require.Zero(t, v)
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}
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func requirePop[T any](t testing.TB, s *GenStack[T], expected T) {
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v, ok := s.Pop()
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require.True(t, ok)
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require.Equal(t, expected, v)
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}
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func TestGenStack_Empty(t *testing.T) {
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s := NewGenStack[int]()
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requirePopEmpty(t, s)
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}
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func TestGenStack_SingleGen(t *testing.T) {
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r := require.New(t)
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s := NewGenStack[int]()
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s.Push(1)
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s.Push(2)
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r.Equal(2, s.Len())
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requirePop(t, s, 2)
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requirePop(t, s, 1)
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requirePopEmpty(t, s)
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}
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func TestGenStack_TwoGen(t *testing.T) {
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r := require.New(t)
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s := NewGenStack[int]()
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s.Push(3)
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s.Push(4)
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s.Push(5)
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r.Equal(3, s.Len())
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s.NextGen()
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r.Equal(3, s.Len())
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s.Push(6)
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s.Push(7)
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r.Equal(5, s.Len())
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requirePop(t, s, 5)
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requirePop(t, s, 4)
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requirePop(t, s, 3)
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requirePop(t, s, 7)
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requirePop(t, s, 6)
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requirePopEmpty(t, s)
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}
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func TestGenStack_MuptiGen(t *testing.T) {
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r := require.New(t)
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s := NewGenStack[int]()
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s.Push(10)
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s.Push(11)
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s.Push(12)
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r.Equal(3, s.Len())
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s.NextGen()
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r.Equal(3, s.Len())
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s.Push(13)
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s.Push(14)
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r.Equal(5, s.Len())
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s.NextGen()
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r.Equal(5, s.Len())
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s.Push(15)
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s.Push(16)
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s.Push(17)
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r.Equal(8, s.Len())
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requirePop(t, s, 12)
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requirePop(t, s, 11)
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requirePop(t, s, 10)
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requirePop(t, s, 14)
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requirePop(t, s, 13)
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requirePop(t, s, 17)
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requirePop(t, s, 16)
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requirePop(t, s, 15)
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requirePopEmpty(t, s)
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}
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@@ -0,0 +1,39 @@
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package genstack
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// stack is a wrapper around an array implementing a stack.
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//
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// We cannot use slice to represent the stack because append might change the
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// pointer value of the slice. That would be an issue in GenStack
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// implementation.
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type stack[T any] struct {
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arr []T
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}
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// push pushes a new element at the top of a stack.
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func (s *stack[T]) push(vs ...T) { s.arr = append(s.arr, vs...) }
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// pop pops the stack top-most element.
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//
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// If stack length is zero, this method panics.
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func (s *stack[T]) pop() T {
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idx := s.len() - 1
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val := s.arr[idx]
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// Avoid memory leak
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var zero T
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s.arr[idx] = zero
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s.arr = s.arr[:idx]
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return val
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}
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// takeAll returns all elements in the stack in order as they are stored - i.e.
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// the top-most stack element is the last one.
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func (s *stack[T]) takeAll() []T {
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arr := s.arr
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s.arr = nil
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return arr
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}
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// len returns number of elements in the stack.
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func (s *stack[T]) len() int { return len(s.arr) }
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