entry: log with spaces between all operands on *ln #25
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@@ -175,33 +175,54 @@ func (entry *Entry) Panicf(format string, args ...interface{}) {
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// Entry Println family functions
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func (entry *Entry) Debugln(args ...interface{}) {
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entry.Debug(args...)
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if entry.Logger.Level >= Debug {
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entry.Debug(entry.sprintlnn(args...))
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}
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}
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func (entry *Entry) Infoln(args ...interface{}) {
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entry.Info(args...)
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if entry.Logger.Level >= Info {
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entry.Info(entry.sprintlnn(args...))
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}
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}
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func (entry *Entry) Println(args ...interface{}) {
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entry.Info(args...)
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entry.Infoln(args...)
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}
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func (entry *Entry) Warnln(args ...interface{}) {
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entry.Warn(args...)
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if entry.Logger.Level >= Warn {
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entry.Warn(entry.sprintlnn(args...))
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}
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}
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func (entry *Entry) Warningln(args ...interface{}) {
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entry.Warn(args...)
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entry.Warnln(args...)
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}
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func (entry *Entry) Errorln(args ...interface{}) {
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entry.Error(args...)
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if entry.Logger.Level >= Error {
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entry.Error(entry.sprintlnn(args...))
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}
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}
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func (entry *Entry) Fatalln(args ...interface{}) {
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entry.Fatal(args...)
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if entry.Logger.Level >= Fatal {
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entry.Fatal(entry.sprintlnn(args...))
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}
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}
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func (entry *Entry) Panicln(args ...interface{}) {
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entry.Panic(args...)
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if entry.Logger.Level >= Panic {
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entry.Panic(entry.sprintlnn(args...))
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}
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}
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// Sprintlnn => Sprint no newline. This is to get the behavior of how
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// fmt.Sprintln where spaces are always added between operands, regardless of
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// their type. Instead of vendoring the Sprintln implementation to spare a
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// string allocation, we do the simplest thing.
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func (entry *Entry) sprintlnn(args ...interface{}) string {
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msg := fmt.Sprintln(args...)
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return msg[:len(msg)-1]
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}
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